Processing Math: Done
Solution 2.2:6c
From Förberedande kurs i matematik 1
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| - | {{ | + | The point of intersection is that point which satisfies the equations of both lines |
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| - | [[Image:2_2_6_c.gif|center]] | + | {{Displayed math||<math>4x+5y+6=0\qquad\text{and}\qquad x=0\,\textrm{.}</math>}} |
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| + | Substituting <math>x=0</math> into <math>4x+5y+6=0</math> gives | ||
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| + | {{Displayed math||<math>4\cdot 0+5y+6=0\quad\Leftrightarrow\quad y=-\frac{6}{5}\,\textrm{.}</math>}} | ||
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| + | This gives the point of intersection as <math>\bigl(0,-\tfrac{6}{5}\bigr)</math>. | ||
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| + | <center>[[Image:2_2_6_c.gif|center]]</center> | ||
Current revision
The point of intersection is that point which satisfies the equations of both lines
Substituting
 0+5y+6=0 y=−56. |
This gives the point of intersection as 
0
−56
