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Solution 2.2:8c

From Förberedande kurs i matematik 1

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Current revision (13:46, 24 September 2008) (edit) (undo)
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By moving the term in
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By moving the term in ''x'' over to the right-hand side and dividing by 3, the inequality can be rewritten as
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<math>x</math>
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over to the right-hand side and dividing by
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<math>3</math>, the inequality can be rewritten as
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{{Displayed math||<math>y\le 2-\frac{2}{3}x\,\textrm{.}</math>}}
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<math>y\le 2-\frac{2}{3}x</math>.
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Then, we see that the area that we should shade consists of all the points under the straight line <math>y=2-\tfrac{2}{3}x\,</math>.
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Then, we see that the area that we should shade consists of all the points under the straight line
 
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<math>y=2-\frac{2}{3}x</math>.
 
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{{NAVCONTENT_START}}
 
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{{NAVCONTENT_STOP}}
 
[[Image:2_2_8_c.gif|center]]
[[Image:2_2_8_c.gif|center]]

Current revision

By moving the term in x over to the right-hand side and dividing by 3, the inequality can be rewritten as

y2−32x.

Then, we see that the area that we should shade consists of all the points under the straight line y=2−32x.


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