Processing Math: Done
Solution 3.3:2d
From Förberedande kurs i matematik 1
(Difference between revisions)
m (Lösning 3.3:2d moved to Solution 3.3:2d: Robot: moved page) |
|||
| Line 1: | Line 1: | ||
| - | {{ | + | If we compare the equality which defines |
| - | < | + | <math>\text{lg 1}</math> |
| - | { | + | |
| + | |||
| + | |||
| + | <math>10^{\text{lg 1}}=1</math> | ||
| + | |||
| + | |||
| + | with | ||
| + | |||
| + | |||
| + | <math>10^{0}=1</math> | ||
| + | |||
| + | |||
| + | we see that | ||
| + | <math>\text{lg 1}=0</math>. | ||
Revision as of 13:14, 25 September 2008
If we compare the equality which defines
with
we see that
