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Solution 2.3:8a

From Förberedande kurs i matematik 1

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Current revision (12:30, 29 September 2008) (edit) (undo)
 
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|align="center"|[[Image:2_3_8_a-1.gif|center]]
|align="center"|[[Image:2_3_8_a-1.gif|center]]
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| width="10px"| 
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|align="center"|[[Image:2_3_8_a-1.gif|center]]
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|align="center"|[[Image:2_3_8_a-2.gif|center]]
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|align="center"|<small>The graph of ''f''(''x'')&nbsp;=&nbsp;''x''²</small>
|align="center"|<small>The graph of ''f''(''x'')&nbsp;=&nbsp;''x''²</small>

Current revision

The curve y=x2 is a parabola with a minimum at the origin according to the figure below on the left and, compared with that curve, y=x2+1 is the same curve but with the number 1 added to the y-coordinate of each point, i.e. the parabola is shifted one unit up in the y-direction.


 
The graph of f(x) = x² The graph of f(x) = x² + 1