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Solution 4.1:4b

From Förberedande kurs i matematik 1

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(Ny sida: {{NAVCONTENT_START}} <center> Bild:4_1_4b.gif </center> {{NAVCONTENT_STOP}})
Current revision (10:30, 7 October 2008) (edit) (undo)
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If we use the distance formula
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<center> [[Bild:4_1_4b.gif]] </center>
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{{NAVCONTENT_STOP}}
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{{Displayed math||<math>d=\sqrt{(x-a)^2+(y-b)^2}</math>}}
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to determine the distance between the points <math>(x,y) = (-2,5)</math> and <math>(a,b) = (3,-1)</math>, we get
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{{Displayed math||<math>\begin{align}
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d &= \sqrt{(-2-3)^2+(5-(-1))^2}\\[5pt]
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&= \sqrt{(-5)^2+6^2}\\[5pt]
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&= \sqrt{25+36}\\[5pt]
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&= \sqrt{61}\,\textrm{.}
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\end{align}</math>}}

Current revision

If we use the distance formula

d=(xa)2+(yb)2 

to determine the distance between the points (xy)=(25) and (ab)=(31), we get

d=(23)2+(5(1))2=(5)2+62=25+36=61.