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Solution 4.2:2b

From Förberedande kurs i matematik 1

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(Ny sida: {{NAVCONTENT_START}} <center> Bild:4_2_2b.gif </center> {{NAVCONTENT_STOP}})
Current revision (14:29, 8 October 2008) (edit) (undo)
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In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle ''v'',
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<center> [[Bild:4_2_2b.gif]] </center>
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{| width="100%"
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|width="50%" align="center"|<math>\sin v = \frac{70}{110}\,\textrm{.}</math>
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|width="50%" align="center"|[[Image:4_2_2_b.gif]]
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|}
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The right-hand side in this equation can be simplified, so that we get
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{{Displayed math||<math>\sin v = \frac{7}{11}\,\textrm{.}</math>}}

Current revision

In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle v,

sinv=70110. Image:4_2_2_b.gif

The right-hand side in this equation can be simplified, so that we get

sinv=711.