From Förberedande kurs i matematik 1

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-	[[Image:4_2_2_b.gif|center]]	+	In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle ''v'',
-	In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle	+	{| width="100%"
-	<math>v</math>,	+	|width="50%" align="center"|<math>\sin v = \frac{70}{110}\,\textrm{.}</math>
-		+	|width="50%" align="center"|[[Image:4_2_2_b.gif]]
-		+	|}
-	<math>\text{sin }v\text{ }=\text{ }{70}/{110}\;</math>.	+
-		+
	The right-hand side in this equation can be simplified, so that we get		The right-hand side in this equation can be simplified, so that we get
-		+	{{Displayed math||<math>\sin v = \frac{7}{11}\,\textrm{.}</math>}}
-	<math>\text{sin }v\text{ }=\text{ }{7}/{11}\;</math>.	+

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Current revision

In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle v,

\displaystyle \sin v = \frac{70}{110}\,\textrm{.}

The right-hand side in this equation can be simplified, so that we get

\displaystyle \sin v = \frac{7}{11}\,\textrm{.}