Solution 4.3:3e
From Förberedande kurs i matematik 1
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- | {{ | + | The angle <math>\pi/2+v</math> makes the same angle with the positive ''y''-axis as the angle ''v'' makes with the positive ''x''-axis, and hence we see that the ''x''-coordinate for <math>\pi/2+v</math> is equal to the ''y''-coordinate for ''v'', but with a change of sign, i.e. |
- | < | + | |
- | + | {{Displayed math||<math>\cos \Bigl(\frac{\pi}{2}+v\Bigr) = -\sin v = -a\,\textrm{.}</math>}} | |
+ | |||
+ | {| align="center" | ||
+ | |align="center"|[[Image:4_3_3_e-1.gif|center]] | ||
+ | |align="center"|[[Image:4_3_3_e-2.gif|center]] | ||
+ | |- | ||
+ | |align="center"|<small>Angle ''v''</small> | ||
+ | |align="center"|<small>Angle π/2 + ''v''</small> | ||
+ | |} |
Current revision
The angle \displaystyle \pi/2+v makes the same angle with the positive y-axis as the angle v makes with the positive x-axis, and hence we see that the x-coordinate for \displaystyle \pi/2+v is equal to the y-coordinate for v, but with a change of sign, i.e.
\displaystyle \cos \Bigl(\frac{\pi}{2}+v\Bigr) = -\sin v = -a\,\textrm{.} |
Angle v | Angle π/2 + v |