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Solution 4.4:2c

From Förberedande kurs i matematik 1

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There are two angles in the unit circle, <math>x=0</math> and <math>x=\pi</math>, whose sine has a value of zero.
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[[Image:4_4_2_c.gif|center]]
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We get the full solution when we add multiples of <math>2\pi</math>,
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{{Displayed math||<math>x = 0+2n\pi\qquad\text{and}\qquad x = \pi + 2n\pi\,,</math>}}
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where ''n'' is an arbitrary integer.
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Note: Because the difference between <math>0</math> and <math>\pi</math> is a half turn, the solutions are repeated every half turn and they can be summarized in one expression,
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{{Displayed math||<math>x=0+n\pi\,,</math>}}
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where ''n'' is an arbitrary integer.

Current revision

There are two angles in the unit circle, x=0 and x=, whose sine has a value of zero.

We get the full solution when we add multiples of 2,

x=0+2nandx=+2n

where n is an arbitrary integer.


Note: Because the difference between 0 and is a half turn, the solutions are repeated every half turn and they can be summarized in one expression,

x=0+n

where n is an arbitrary integer.