1.2 Exercises
From Förberedande kurs i matematik 1
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| - | {{ | + | {{Not selected tab|[[1.2 Fractional arithmetic|Theory]]}} |
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===Exercise 1.2:1=== | ===Exercise 1.2:1=== | ||
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| - | + | Express as a single fraction | |
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===Exercise 1.2:4=== | ===Exercise 1.2:4=== | ||
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| - | Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form. | + | Simplify the following by writing each part as one fraction. The fraction should be in the simplest possible form. |
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===Exercise 1.2:5=== | ===Exercise 1.2:5=== | ||
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| - | Simplify the following by writing each part as one fraction. The fraction should be in simplest possible form. | + | Simplify the following by writing each part as one fraction. The fraction should be in the simplest possible form. |
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Current revision
| Theory | Exercises |
Exercise 1.2:1
Express as a single fraction
| a) | | b) | | c) | |
| d) | | e) |
Answer | Solution a | Solution b | Solution c | Solution d | Solution e
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Exercise 1.2:2
Determine the lowest common denominator of
| a) | | b) | |
| c) | | d) | |
Answer | Solution a | Solution b | Solution c | Solution d
Exercise 1.2:3
Calculate the following by using the lowest common denominator.
| a) | | b) | |
Exercise 1.2:4
Simplify the following by writing each part as one fraction. The fraction should be in the simplest possible form.
| a) | | b) | | c) | |
Answer | Solution a | Solution b | Solution c
Exercise 1.2:5
Simplify the following by writing each part as one fraction. The fraction should be in the simplest possible form.
| a) | | b) | | c) | \displaystyle \displaystyle\frac{\displaystyle\frac{3}{10}\displaystyle-\frac{1}{5}}{\displaystyle\frac{7}{8}\displaystyle-\frac{3}{16}} |
Answer | Solution a | Solution b | Solution c
Exercise 1.2:6
Simplify \displaystyle \ \,\displaystyle \frac{\displaystyle \frac{2}{\displaystyle 3+\frac{1}{2}}\displaystyle + \frac{\displaystyle \frac{1}{2}}{\displaystyle \frac{1}{4}\displaystyle -\frac{1}{3}}}{\displaystyle \frac{1}{2}\displaystyle - \frac{3}{\displaystyle 2-\frac{2}{7}}}
