Solution 4.3:4a
From Förberedande kurs i matematik 1
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| - | + | The Pythagorean identity <math>\cos^2 v + \sin^2 v = 1</math> gives us directly that | |
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| - | {{ | + | {{Displayed math||<math>\sin^2 v = 1-\cos^2 v = 1-b^2\,\textrm{.}</math>}} |
Current revision
The Pythagorean identity \displaystyle \cos^2 v + \sin^2 v = 1 gives us directly that
| \displaystyle \sin^2 v = 1-\cos^2 v = 1-b^2\,\textrm{.} |
