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Solution 2.1:3c

From Förberedande kurs i matematik 1

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The expression can be rewritten as <math> x^2+2\cdot 3\cdot x+3^2 </math> and then we see that it can be factorized, using the squaring rule <math> x^2+2ax+a^2=(x+a)^2</math>, as
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The expression can be rewritten as <math> x^2+2\cdot 3\cdot x+3^2 </math> and then we see that it can be factorized, using the squaring rule <math> x^2+2ax+a^2=(x+a)^2</math> as
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:<math> x^2+6x+9 =x^2+2\cdot 3\cdot x+3^2=(x+3)^2.</math>
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Current revision

The expression can be rewritten as x2+23x+32 and then we see that it can be factorized, using the squaring rule x2+2ax+a2=(x+a)2, as

x2+6x+9=x2+23x+32=(x+3)2.
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