From Förberedande kurs i matematik 1

Revision as of 06:40, 21 August 2008 (edit) Tekbot (Talk | contribs) m (Robot: Automated text replacement (-[[Bild: +[[Image:)) ← Previous diff		Current revision (12:28, 24 September 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	Because the straight line is to have a slope of <math>-3</math>, its equation can be written as
-	<center> [[Image:2_2_5b.gif]] </center>	+
		+	{{Displayed math||<math>y=-3x+m\,,</math>}}
		+
		+	where ''m'' is a constant. If the line is also to pass through the point (''x'',''y'')&nbsp;= (1,-2), the point must satisfy the equation of the line,
		+
		+	{{Displayed math||<math>-2=-3\cdot 1+m\,,</math>}}
		+
		+	which gives that <math>m=1</math>.
		+
		+	The answer is thus that the equation of the line is <math>y=-3x+1</math>.
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		+
	[[Image:1_2_2_5_b_ss1.jpg|center|300px]]		[[Image:1_2_2_5_b_ss1.jpg|center|300px]]
-	{{NAVCONTENT_STOP}}

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Current revision

Because the straight line is to have a slope of \displaystyle -3, its equation can be written as

\displaystyle y=-3x+m\,,

where m is a constant. If the line is also to pass through the point (x,y) = (1,-2), the point must satisfy the equation of the line,

\displaystyle -2=-3\cdot 1+m\,,

which gives that \displaystyle m=1.

The answer is thus that the equation of the line is \displaystyle y=-3x+1.