From Förberedande kurs i matematik 1

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-	{{NAVCONTENT_START}}	+	By completing the square, we can rewrite the function as
-	<center> [[Image:2_3_8c.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>f(x) = x^{2}-6x+11 = (x-3)^{2} - 3^{2} + 11 = (x-3)^{2} + 2,</math>}}
-	[[Image:2_3_8_c.gif|center]]	+
		+	and when the function is written in this way, we see that the graph <math>y = (x-3)^{2} + 2</math> is the same curve as the parabola <math>y=x^{2}</math>, but shifted two units up and three units to the right (see sub-exercise a and b).
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		+	{| align="center"
		+	|align="center"|[[Image:2_3_8_c-1.gif|center]]
		+	||&nbsp;
		+	|align="center"|[[Image:2_3_8_c-2.gif|center]]
		+	|-
		+	|align="center"|<small>The graph of ''f''(''x'')&nbsp;=&nbsp;''x''²</small>
		+	||
		+	|align="center"|<small>The graph of ''f''(''x'')&nbsp;=&nbsp;''x''²&nbsp;-&nbsp;6x&nbsp;+&nbsp;11</small>
		+	|}

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Current revision

By completing the square, we can rewrite the function as

\displaystyle f(x) = x^{2}-6x+11 = (x-3)^{2} - 3^{2} + 11 = (x-3)^{2} + 2,

and when the function is written in this way, we see that the graph \displaystyle y = (x-3)^{2} + 2 is the same curve as the parabola \displaystyle y=x^{2}, but shifted two units up and three units to the right (see sub-exercise a and b).

The graph of f(x) = x²		The graph of f(x) = x² - 6x + 11