Solution 4.2:2e
From Förberedande kurs i matematik 1
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- | {{ | + | This exercise is somewhat of a trick question, because we don't need any trigonometry to solve it. |
- | < | + | |
- | + | Two angles are given in the triangle (the 60° angle and the right-angle) and thus we can use the fact that the sum of all the angles in a triangle is 180°, | |
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+ | {{Displayed math||<math>v + 60^{\circ} + 90^{\circ} = 180^{\circ}\,,</math>}} | ||
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+ | which gives | ||
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+ | {{Displayed math||<math>v = 180^{\circ} - 60^{\circ} - 90^{\circ} = 30^{\circ}\,\textrm{.}</math>}} |
Current revision
This exercise is somewhat of a trick question, because we don't need any trigonometry to solve it.
Two angles are given in the triangle (the 60° angle and the right-angle) and thus we can use the fact that the sum of all the angles in a triangle is 180°,
\displaystyle v + 60^{\circ} + 90^{\circ} = 180^{\circ}\,, |
which gives
\displaystyle v = 180^{\circ} - 60^{\circ} - 90^{\circ} = 30^{\circ}\,\textrm{.} |