Solution 1.1:2c
From Förberedande kurs i matematik 1
(Difference between revisions)
m (Lösning 1.1:2c moved to Solution 1.1:2c: Robot: moved page) |
|||
Line 1: | Line 1: | ||
{{NAVCONTENT_START}} | {{NAVCONTENT_START}} | ||
- | + | We can divide up the whole expression into two separate parts | |
<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center> | <center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,}</math></center> | ||
- | + | which we first calculate and then combine. | |
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
- | + | The first part of the expression equals | |
<center><math>3\cdot(-7) = -21</math></center> | <center><math>3\cdot(-7) = -21</math></center> | ||
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
- | + | whilst the second expression becomes. | |
<center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center> | <center><math>4\cdot(6-5) = 4\cdot 1 = 4\,</math>.</center> | ||
{{NAVCONTENT_STEP}} | {{NAVCONTENT_STEP}} | ||
- | + | Combining, we obtain | |
<center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center> | <center><math>\bbox[#FFEEAA;,1.5pt]{\,3\cdot(-7)\,}-\bbox[#FFEEAA;,1.5pt]{\,4\cdot(6-5)\,} = \bbox[#FFEEAA;,1.5pt]{\,-21\,}-\bbox[#FFEEAA;,1.5pt]{\,4\,} = -25\,</math>.</center> | ||
{{NAVCONTENT_STOP}} | {{NAVCONTENT_STOP}} | ||
<!--<center> [[Image:1_1_2c.gif]] </center> --> | <!--<center> [[Image:1_1_2c.gif]] </center> --> |
Current revision
We can divide up the whole expression into two separate parts
which we first calculate and then combine.
The first part of the expression equals
whilst the second expression becomes.
Combining, we obtain