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Solution 2.1:3b

From Förberedande kurs i matematik 1

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m (Lösning 2.1:3b moved to Solution 2.1:3b: Robot: moved page)
Current revision (08:30, 23 September 2008) (edit) (undo)
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If we take out the factor 5, we see that the expression can be factorized using the conjugate rule
If we take out the factor 5, we see that the expression can be factorized using the conjugate rule
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<math> \qquad \begin{align}
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{{Displayed math||<math>\begin{align}
5x^2-20&=5(x^4-4)\\
5x^2-20&=5(x^4-4)\\
&= 5(x^2-2^2)\\
&= 5(x^2-2^2)\\
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&= 5(x+2)(x-2)
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&= 5(x+2)(x-2)\,\textrm{.}
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\end{align}
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\end{align}</math>}}
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</math>
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<!--<center> [[Image:2_1_3b.gif]] </center>-->
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{{NAVCONTENT_STOP}}
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Current revision

If we take out the factor 5, we see that the expression can be factorized using the conjugate rule

5x2−20=5(x4−4)=5(x2−22)=5(x+2)(x−2).
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