Solution 2.1:3c

From Förberedande kurs i matematik 1

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m (Lösning 2.1:3c moved to Solution 2.1:3c: Robot: moved page)
Current revision (08:31, 23 September 2008) (edit) (undo)
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The expression can be rewritten as <math> x^2+2\cdot 3\cdot x+3^2 </math> and then we see that it can be factorized, using the squaring rule <math> x^2+2ax+a^2=(x+a)^2</math>, as
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<!--center> [[Image:2_1_3c.gif]] </center-->
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The expression can be rewritten as <math> x^2+2\cdot 3\cdot x+3^2 </math> and then we see that it can be factorized, using the squaring rule <math> x^2+2ax+a^2=(x+a)^2</math> as
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:<math> x^2+6x+9 =x^2+2\cdot 3\cdot x+3^2=(x+3)^2.</math>
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{{Displayed math||<math> x^2+6x+9 =x^2+2\cdot 3\cdot x+3^2=(x+3)^2\textrm{.}</math>}}
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Current revision

The expression can be rewritten as \displaystyle x^2+2\cdot 3\cdot x+3^2 and then we see that it can be factorized, using the squaring rule \displaystyle x^2+2ax+a^2=(x+a)^2, as

\displaystyle x^2+6x+9 =x^2+2\cdot 3\cdot x+3^2=(x+3)^2\textrm{.}
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