Processing Math: Done
Solution 1.2:2d
From Förberedande kurs i matematik 1
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<math>\begin{align} | <math>\begin{align} | ||
& \frac{2}{5\centerdot 3\centerdot 3}\centerdot \frac{5}{5}+\frac{1}{3\centerdot 5\centerdot 5}\centerdot \frac{3}{3} \\ | & \frac{2}{5\centerdot 3\centerdot 3}\centerdot \frac{5}{5}+\frac{1}{3\centerdot 5\centerdot 5}\centerdot \frac{3}{3} \\ | ||
+ | & \\ | ||
& =\frac{2}{5\centerdot 3\centerdot 3\centerdot 5}+\frac{3}{3\centerdot 5\centerdot 5\centerdot 3} \\ | & =\frac{2}{5\centerdot 3\centerdot 3\centerdot 5}+\frac{3}{3\centerdot 5\centerdot 5\centerdot 3} \\ | ||
+ | & \\ | ||
& =\frac{10}{225}+\frac{3}{225} \\ | & =\frac{10}{225}+\frac{3}{225} \\ | ||
\end{align}</math> | \end{align}</math> | ||
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Revision as of 12:52, 11 September 2008
If we divide up the denominators into their smallest possible integer factors,
9=5
3
375=3
25=3
5
5
the expression can be written as
3
3+13
5
5
and then we see that the denominators have
5
3
3
55+13
5
5
33=25
3
3
5+33
5
5
3=10225+3225
The lowest common denominator is