Solution 4.2:4d

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Current revision (10:37, 9 October 2008) (edit) (undo)
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If we use the unit circle and mark on the angle
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If we use the unit circle and mark on the angle <math>\pi</math>, we see immediately that <math>\cos \pi = -1</math> and <math>\sin \pi = 0\,</math>.
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<math>\pi </math>, we see immediately that
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<math>\text{cos }\pi \text{ }=-\text{1 }</math>
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and
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<math>\text{sin }\pi \text{ }=0</math>.
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[[Image:4_2_4_d.gif|center]]
[[Image:4_2_4_d.gif|center]]
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Thus,
Thus,
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{{Displayed math||<math>\tan \pi =\frac{\sin \pi }{\cos \pi }=\frac{0}{-1}=0\,\textrm{.}</math>}}
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<math>\tan \pi =\frac{\sin \pi }{\cos \pi }=\frac{0}{-1}=0</math>
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Current revision

If we use the unit circle and mark on the angle \displaystyle \pi, we see immediately that \displaystyle \cos \pi = -1 and \displaystyle \sin \pi = 0\,.

Thus,

\displaystyle \tan \pi =\frac{\sin \pi }{\cos \pi }=\frac{0}{-1}=0\,\textrm{.}
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