From Förberedande kurs i matematik 1

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	The formula for double angles gives		The formula for double angles gives
		+	{{Displayed math||<math>\sin 2v=2\sin v\cos v</math>}}
-	<math>\sin 2v=2\sin v\cos v</math>	+	and from exercise b, we have <math>\sin v = \sqrt{1-b^2}\,</math>. Thus,
-		+	{{Displayed math||<math>\sin 2v = 2b\sqrt{1-b^2}\,\textrm{.}</math>}}
-	and from exercise b, we have	+
-	<math>\sin v=\sqrt{1-b^{2}}</math>	+
-		+
-		+
-	Thus,	+
-		+
-		+
-	<math>\sin 2v=2b\sqrt{1-b^{2}}</math>	+

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Current revision

The formula for double angles gives

\displaystyle \sin 2v=2\sin v\cos v

and from exercise b, we have \displaystyle \sin v = \sqrt{1-b^2}\,. Thus,

\displaystyle \sin 2v = 2b\sqrt{1-b^2}\,\textrm{.}