Solution 2.1:1a

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
Line 1: Line 1:
<!--center> [[Bild:2_1_1a.gif]] </center-->
<!--center> [[Bild:2_1_1a.gif]] </center-->
-
Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x. </math>
+
Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x, </math>
-
:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x </math>
+
:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x. </math>

Revision as of 08:15, 13 August 2008


Using the distributivity rule, we can multiply the factor \displaystyle 3x into the bracket \displaystyle (x-1) . Each term in \displaystyle (x-1) is then to be multiplied by \displaystyle 3x,

\displaystyle 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x.