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Solution 2.1:3f

From Förberedande kurs i matematik 1

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<math> \qquad 16x^2+8x+1=(4x)^2 +2\cdot 4x +1 </math>
<math> \qquad 16x^2+8x+1=(4x)^2 +2\cdot 4x +1 </math>
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and because <math> y^2 +2y+1=(y+1)^2 </math> we obtain
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and since <math> y^2 +2y+1=(y+1)^2 </math> we obtain
<math> \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2 </math>
<math> \qquad (4x)^2 +2\cdot 4x +1= (4x+1)^2 </math>
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Revision as of 13:24, 13 August 2008

Treating 4x as one term, we can write

16x2+8x+1=(4x)2+24x+1

and since y2+2y+1=(y+1)2 we obtain

(4x)2+24x+1=(4x+1)2

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