Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Solution 1.2:1c

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
m (Lösning 1.2:1c moved to Solution 1.2:1c: Robot: moved page)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
+
We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,
-
<center> [[Image:1_2_1c.gif]] </center>
+
 
-
{{NAVCONTENT_STOP}}
+
 
 +
<math>\frac{1}{6}-\frac{2}{5}=\frac{1\centerdot 5}{6\centerdot 5}-\frac{2\centerdot 6}{5\centerdot 6}=\frac{5}{30}-\frac{12}{30}</math>
 +
 
 +
 
 +
Then the numerators can be subtracted:
 +
 
 +
 
 +
<math>\frac{5}{30}-\frac{12}{30}=\frac{5-12}{30}=\frac{-7}{30}=-\frac{7}{30}</math>

Revision as of 11:37, 11 September 2008

We multiply the top and bottom of each fraction by the other fraction's denominator so that they have a common denominator,


61−52=6515−5626=530−3012


Then the numerators can be subtracted:


530−3012=305−12=30−7=−730

Retrieved from "http://wiki.math.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_1.2:1c"