Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Solution 4.2:1d

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
m (Lösning 4.2:1d moved to Solution 4.2:1d: Robot: moved page)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
 
-
<center> [[Image:4_2_1d.gif]] </center>
 
-
{{NAVCONTENT_STOP}}
 
[[Image:4_2_1_d.gif|center]]
[[Image:4_2_1_d.gif|center]]
 +
 +
The side marked
 +
<math>x</math>
 +
is the hypotenuse in the right-angled triangle and the side of length
 +
<math>\text{16}</math>
 +
is the adjacent to the angle of
 +
<math>\text{2}0^{\circ }</math>.
 +
 +
 +
By writing the quotient for
 +
<math>\text{cos20}^{\circ }</math>, we obtain the relation
 +
 +
 +
<math>\text{cos20}^{\circ }=\frac{16}{x}</math>
 +
 +
 +
and this gives
 +
 +
 +
<math>x=\frac{16}{\text{cos20}^{\circ }}\quad \left( \approx 17.0 \right).</math>

Revision as of 11:08, 28 September 2008

The side marked x is the hypotenuse in the right-angled triangle and the side of length 16 is the adjacent to the angle of 20.


By writing the quotient for cos20, we obtain the relation


cos20=x16


and this gives


x=16cos20170 

Retrieved from "http://wiki.math.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_4.2:1d"