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Solution 4.2:4f

From Förberedande kurs i matematik 1

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m (Lösning 4.2:4f moved to Solution 4.2:4f: Robot: moved page)
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{{NAVCONTENT_START}}
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If we add
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<center> [[Image:4_2_4f.gif]] </center>
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<math>2\pi </math>
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{{NAVCONTENT_STOP}}
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to
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<math>-\frac{5\pi }{3}</math>, we get a new angle in the first quadrant which corresponds to the same point on the unit circle as the old angle
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<math>-\frac{5\pi }{3}</math>
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and consequently has the same tangent value:
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<math>\begin{align}
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& \tan \left( -\frac{5\pi }{3} \right)=\tan \left( -\frac{5\pi }{3}+2\pi \right)=\tan \frac{\pi }{3} \\
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& =\frac{\sin \frac{\pi }{3}}{\cos \frac{\pi }{3}}=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\sqrt{3} \\
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\end{align}</math>

Revision as of 13:27, 28 September 2008

If we add 2 to −35, we get a new angle in the first quadrant which corresponds to the same point on the unit circle as the old angle −35 and consequently has the same tangent value:


tan−35=tan−35+2=tan3=sin3cos3=2123=3

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