Solution 4.3:4c

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
m (Lösning 4.3:4c moved to Solution 4.3:4c: Robot: moved page)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
+
The formula for double angles gives
-
<center> [[Image:4_3_4c.gif]] </center>
+
 
-
{{NAVCONTENT_STOP}}
+
 
 +
<math>\sin 2v=2\sin v\cos v</math>
 +
 
 +
 
 +
and from exercise b, we have
 +
<math>\sin v=\sqrt{1-b^{2}}</math>
 +
 
 +
 
 +
Thus,
 +
 
 +
 
 +
<math>\sin 2v=2b\sqrt{1-b^{2}}</math>

Revision as of 11:44, 29 September 2008

The formula for double angles gives


\displaystyle \sin 2v=2\sin v\cos v


and from exercise b, we have \displaystyle \sin v=\sqrt{1-b^{2}}


Thus,


\displaystyle \sin 2v=2b\sqrt{1-b^{2}}

Retrieved from "http://wiki.math.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_4.3:4c"