Processing Math: Done
Solution 4.3:5
From Förberedande kurs i matematik 1
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- | + | An often-used technique to calculate | |
- | < | + | <math>\text{cos }v</math> |
- | + | and | |
- | { | + | <math>\text{tan }v</math>, given the sine value of an acute angle, is to draw the angle |
- | < | + | <math>v</math> |
- | {{ | + | in a right-angled triangle which has two sides arranged so that |
+ | <math>\text{sin }v={5}/{7}\;</math>. | ||
+ | |||
+ | |||
[[Image:4_3_5_1.gif|center]] | [[Image:4_3_5_1.gif|center]] | ||
+ | |||
+ | Using Pythagoras' theorem, we can determine the length of the third side in the triangle. | ||
+ | |||
+ | |||
[[Image:4_3_5_2.gif|center]] | [[Image:4_3_5_2.gif|center]] | ||
+ | |||
+ | |||
+ | <math>x^{2}+5^{2}=7^{2}</math> | ||
+ | which gives that | ||
+ | <math>x=\sqrt{7^{2}-5^{2}}=\sqrt{24}=2\sqrt{6}</math> | ||
+ | |||
+ | Then, using the definition of cosine and tangent, | ||
+ | |||
+ | |||
+ | <math>\begin{align} | ||
+ | & \cos v=\frac{x}{7}=\frac{2\sqrt{6}}{7}, \\ | ||
+ | & \tan v=\frac{5}{x}=\frac{5}{2\sqrt{6}} \\ | ||
+ | \end{align}</math> | ||
+ | |||
+ | |||
+ | NOTE: Note that the right-angled triangle that we use is just a tool and has nothing to do with the triangle that is referred to in the question. |
Revision as of 12:11, 29 September 2008
An often-used technique to calculate
7
Using Pythagoras' theorem, we can determine the length of the third side in the triangle.
72−52=
24=2
6
Then, using the definition of cosine and tangent,
6
tanv=x5=52
6
NOTE: Note that the right-angled triangle that we use is just a tool and has nothing to do with the triangle that is referred to in the question.