Solution 4.3:4a

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
Current revision (14:07, 9 October 2008) (edit) (undo)
m
 
Line 1: Line 1:
-
The Pythagorean identity
+
The Pythagorean identity <math>\cos^2 v + \sin^2 v = 1</math> gives us directly that
-
<math>\cos ^{2}v+\sin ^{2}v=1</math>
+
-
gives us directly that
+
-
 
+
{{Displayed math||<math>\sin^2 v = 1-\cos^2 v = 1-b^2\,\textrm{.}</math>}}
-
<math>\sin ^{2}v=1-\cos ^{2}v=1-b^{2}</math>
+

Current revision

The Pythagorean identity \displaystyle \cos^2 v + \sin^2 v = 1 gives us directly that

\displaystyle \sin^2 v = 1-\cos^2 v = 1-b^2\,\textrm{.}
Retrieved from "http://wiki.math.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_4.3:4a"