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Solution 4.3:4c

From Förberedande kurs i matematik 1

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Current revision (14:12, 9 October 2008) (edit) (undo)
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The formula for double angles gives
The formula for double angles gives
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{{Displayed math||<math>\sin 2v=2\sin v\cos v</math>}}
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<math>\sin 2v=2\sin v\cos v</math>
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and from exercise b, we have <math>\sin v = \sqrt{1-b^2}\,</math>. Thus,
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{{Displayed math||<math>\sin 2v = 2b\sqrt{1-b^2}\,\textrm{.}</math>}}
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and from exercise b, we have
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<math>\sin v=\sqrt{1-b^{2}}</math>
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Thus,
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<math>\sin 2v=2b\sqrt{1-b^{2}}</math>
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Current revision

The formula for double angles gives

sin2v=2sinvcosv

and from exercise b, we have sinv=1−b2 . Thus,

sin2v=2b1−b2. 
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