Solution 4.4:4
From Förberedande kurs i matematik 1
The idea is first to find the general solution to the equation and then to see which angles lie between
If we start by considering the expression
=110
There is then a further solution which satisfies
2v+10
360
−90
=20
=270
−20
=250
There is then a further solution which satisfies
2v+10
360
−90
=20
=270
−20
=250
FIGURE1 FIGURE2
Now it is easy to write down the general solution,
=110
+n
360
=250
+n
360
and if we make
+n
180
+n
180
For different values of the integers
n=−2n=−1n=0n=1n=2n=3
v=50
−2
180
=−310
v=50
−1
180
=−130
v=50
+0
180
=50
v=50
+1
180
=230
v=50
+2
180
=410
v=50
+3
180
=590
v=120
−2
180
=−240
v=120
−1
180
=−60
v=120
+0
180
=120
v=120
+1
180
=300
v=120
+2
180
=480
v=120
+3
180
=660
From the table, we see that the solutions that are between
v=120
v=230