Processing Math: Done
Solution 1.2:2d
From Förberedande kurs i matematik 1
If we divide up the denominators into their smallest possible integer factors,
9=5 3 3 =3 25=3 5 5![]() |
the expression can be written as
3 3+13 5 5 |
and then we see that the denominators have
5
3 3 55+13 5 5 33=25 3 3 5+33 5 5 3=10225+3225. |
The lowest common denominator is 225.

