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Solution 2.1:6d

From Förberedande kurs i matematik 1

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First, we simplify the numerator and denominator for the whole fraction by rewriting as


ab+b2a+b=aba+ba+b+b2a+b=a+baba+b+b2a+ba2b2+b2=a2a+b


1a+bab2=1a+b2ab2=a+b2a+b2a+b2ab2=a+b2a+b2ab2=a+b2a2+2ab+b2a22ab+b2=4aba+b2


The whole fraction is therefore


1a+bab2ab+b2a+b=a2a+b4aba+b2=a2a+b4aba+b2=4baa+b