Solution 2.2:2a
From Förberedande kurs i matematik 1
If we divide up the denominators that appear in the equation into small integer factors
3
3
3
3=18
3
3
3
3
65x−2
3
3
9x+2=2
3
3
21
3
5x−2
x+2
=3
3
We can rewrite the left-hand side as
5x−2
x+2
=15x−2x−4=13x−4
We can now solve this first-degree equation by carrying out simple arithmetical calculations so as to get
1. Add 4 to both sides:
which gives
2. Divide both sides by 13:
which gives the answer
The equation has
When we have obtained an answer, it is important to go back to the original equation to check that
LHS =
1−91
2=65−93=65−31=65−3
21
2=65−2=63=21