Solution 4.2:2b

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In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle \displaystyle v,


\displaystyle \text{sin }v\text{ }=\text{ }{70}/{110}\;.


The right-hand side in this equation can be simplified, so that we get


\displaystyle \text{sin }v\text{ }=\text{ }{7}/{11}\;.