Processing Math: Done

From Förberedande kurs i matematik 1

First, we multiply the second bracket by x from the first bracket,

x+23x2−x+5=x3x2−xx+x5+ 

Then, do the same for 2 from the first bracket:

x+23x2−x+5=3x3−x2+5x+23x2−2x+25 

Now, collect together x3-, x2-, x- and the constant terms:

3x3+−1+6x2+5−2x+10=3x3+5x2+3x+10 

The coefficient in front of x2 is 5 and the coefficient in front of x is 3.