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Solution 2.1:4c

From Förberedande kurs i matematik 1

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Instead of multiplying together the whole expression, and then reading off the coefficients, we investigate which terms from the three brackets together give terms in x1 and x2.

If we start with the term in x, we see that there is only one combination of a term from each bracket which, when multiplied, gives x1,


xx3+x51+3x+5x227x2x4=+x12+ 

so, the coefficient in front of x is 12=2.

As for x2, we also have only one possible combination:


xx3+x51+3x+5x227x2x4=+x3x2+ 


The coefficient in front of x2 is 32=6