Solution 2.2:6c
From Förberedande kurs i matematik 1
The point of intersection is that point which satisfies the equations of both lines
\displaystyle 4x+5y+6=0
and
\displaystyle x=0.
Substituting \displaystyle 4x+5y+6=0 into \displaystyle x=0 gives
\displaystyle 4\centerdot 0+5y+6=0\ \Leftrightarrow \ y=-\frac{6}{5}
This gives the point of intersection as
\displaystyle \left( 0 \right.,\left. -\frac{6}{5} \right).
