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Solution 2.1:1d

From Förberedande kurs i matematik 1

Revision as of 07:48, 23 September 2008 by Tek (Talk | contribs)
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After x3y2 are multiplied inside the bracket, we can eliminate factors which occur in both the numerator and denominator,

x3y2y11xy+1=x3y2y1x3y21xy+x3y21=yx3y2xyx3y2+x3y2=x3yx2y+x3y2

where we have used

yx3y2xyx3y2=yx3yy=x3y=xyxxxyy=xxy=x2y.