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Solution 2.1:1e

From Förberedande kurs i matematik 1

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If we use the rule for squaring (ab)2=a22ab+b2 with a=x and b=7, we obtain directly that

(x7)2=x22x7+72=x214x+49.

An alternative is to write the square as (x7)(x7) and then multiply the brackets in two steps

(x7)(x7)=(x7)x(x7)7=xx7x(x777)=x27x(7x49)=x27x7x+49=x2(7+7)x+49=x214x+49.

In the line that has been marked with an asterisk, we have removed the bracket and at the same time changed signs on all terms inside the bracket.