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Solution 2.1:5c

From Förberedande kurs i matematik 1

Revision as of 10:57, 23 September 2008 by Tek (Talk | contribs)
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The fraction can be further simplified if it is possible to factorize and eliminate common factors from the numerator and denominator. Both numerator and denominator are already factorized to a certain extent, but we can go further with the numerator and break it up into linear factors by using the conjugate rule

3x212x21=3(x24)=3(x+2)(x2)=(x+1)(x1).

The whole expression is therefore equal to

(x+1)(x+2)3(x+2)(x2)(x+1)(x1)=3(x2)(x1).

Note: One can of course expand the expression to get 3x29x+6 as the answer.