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Solution 2.1:6c

From Förberedande kurs i matematik 1

Revision as of 11:39, 23 September 2008 by Tek (Talk | contribs)
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Because the denominators are a2ab=a(ab) and ab, both terms will have a common denominator a(ab) if the top and bottom of the second term are multiplied by a,

a2b2a+b2ab=2a+ba(ab)2abaa=a(ab)2a+b2a=ba(ab).