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Solution 2.1:7b

From Förberedande kurs i matematik 1

Revision as of 12:00, 23 September 2008 by Tek (Talk | contribs)
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The denominators x1 and x2 do not have a common denominator, so the lowest common denominator is x2(x1). We treat all three terms so that they have a common denominator and then start simplifying

x+1x1+1x2=xx2(x1)x2(x1)+1x1x2x2+1x2x1x1=x2(x1)x3(x1)+x2+(x1)=x2(x1)x4x3+x2+x1.