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Solution 2.2:6c

From Förberedande kurs i matematik 1

Revision as of 13:10, 24 September 2008 by Tek (Talk | contribs)
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The point of intersection is that point which satisfies the equations of both lines

4x+5y+6=0andx=0.

Substituting x=0 into 4x+5y+6=0 gives

40+5y+6=0y=56.

This gives the point of intersection as 056 .