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Solution 2.1:8b
From Förberedande kurs i matematik 1
The fraction consists of the numerator
x−3
\displaystyle \begin{align}
& \frac{\frac{3}{x}-\frac{1}{x}}{\frac{1}{x-3}}=\frac{\frac{2}{x}}{\frac{1}{x-3}}=\frac{\frac{2}{x}}{\frac{1}{x-3}}\centerdot \frac{x\left( x-3 \right)}{x\left( x-3 \right)} \\
& \\
& =\frac{\frac{2}{x}\centerdot x\left( x-3 \right)}{\frac{1}{x-3}\centerdot x\left( x-3 \right)}=\frac{2\left( x-3 \right)}{x} \\
\end{align}