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Solution 3.3:2h
From Förberedande kurs i matematik 1
The argument in the logarithm can be rewritten as
1102=10−2
and then the log law
lgab=blga
gives the rest:
\displaystyle \lg \frac{1}{10^{2}}=\lg 10^{-2}=\left( -2 \right)\centerdot \lg 10=\left( -2 \right)\centerdot 1=-2