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Solution 3.3:2h

From Förberedande kurs i matematik 1

Revision as of 13:46, 25 September 2008 by Ian (Talk | contribs)
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The argument in the logarithm can be rewritten as 1102=102 and then the log law lgab=blga gives the rest:


\displaystyle \lg \frac{1}{10^{2}}=\lg 10^{-2}=\left( -2 \right)\centerdot \lg 10=\left( -2 \right)\centerdot 1=-2