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Solution 3.3:3a

From Förberedande kurs i matematik 1

Revision as of 13:57, 25 September 2008 by Ian (Talk | contribs)
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By writing the argument 8 as 8=24=222=23, the logarithm law, lgab=blga, gives


log28=log223=3log22=31=3


where we have used log22=1.