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Solution 4.1:6c

From Förberedande kurs i matematik 1

Revision as of 11:45, 27 September 2008 by Ian (Talk | contribs)
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What we need to do is to rewrite the equation in the standard form


xa2+yb2=r2 


because then we can read off the circle's centre ab  and radius, r.

In our case, we need only take out the factor  3 from the brackets on the left-hand side


3x12+3y+72=32x312+32y+372=9x312+9y+372


and then divide both sides by 9 , so as to get the equation in the desired form:


x312+y+372=910 

Because the right-hand side can be written as 9102  and the term y+372  as

y372 , the equation describes a circle with its centre at 3137  and radius 910=310