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Solution 4.2:6

From Förberedande kurs i matematik 1

Revision as of 08:29, 29 September 2008 by Ian (Talk | contribs)
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We can work out the length we are looking for by taking the difference ab of the sides a and b in the triangles below:

If we take the tangent of the given angle in each triangle, we easily obtain a and b:


\displaystyle a=1\centerdot \tan 60^{\circ }=\frac{\sin 60^{\circ }}{\cos 60^{\circ }}=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\sqrt{3}