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Solution 4.4:3d

From Förberedande kurs i matematik 1

Revision as of 09:57, 1 October 2008 by Ian (Talk | contribs)
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First, we observe from the unit circle that the equation has two solutions for 03x360,


3x=15 and 3x=18015=165


This means that all of the equation's solutions are


3x=15+n360 and 3x=165+n360


for all integers n, i.e.


x=5+n120 and x=55+n120